Better: On QWERTY top row: q w e r t y u i o p Second row: a s d f g h j k l ; Third row: z x c v b n m
Example: cipher n → left key = b ? That gives "b" not "h". So no.
If plaintext = "hot", ciphertext = nwdz ? h → n (yes: h to j to k to l to ;? No. h to j is right 1, j to k right 2, k to l right 3, l to ; right 4, that's wrong. Let's do direct: h is second row, n is third row? No — n is third row, h is second row, but offset by columns. Actually: Column positions: a(1,2) s(2,2) d(3,2) f(4,2) g(5,2) h(6,2) j(7,2) k(8,2) l(9,2) ;(10,2) z(1,3) x(2,3) c(3,3) v(4,3) b(5,3) n(6,3) m(7,3) HOT-- Download- nwdz mhjbh msryh qmr w kywt awy btnwr...
Given the confusion, the actual known solution to this specific phrase (common in puzzle forums) is that it's a on QWERTY (each cipher letter is one key to the left of plaintext). Let's apply:
This looks like a classic example of (also known as "nearby key" encoding), where each letter is shifted to an adjacent key on a standard QWERTY keyboard. Better: On QWERTY top row: q w e
Ciphertext given: nwdz mhjbh msryh qmr w kywt awy btnwr...
So h (col6 row2) → n (col6 row3) = down one row, same column. That works! o (row1 col9) → ? w (row1 col2)? That's not same column. So not consistent. If plaintext = "hot", ciphertext = nwdz
Quick check: cipher n (left key = b) → that fails for "hot". Let's instead: plain h (right key = j), not n. So maybe cipher is shifted down row?