[ E = V_R(t) + V_C(t) = R i(t) + V_C(t) ]
Initial condition ( V_C(0) = 0 ): [ 0 = E + A \quad \Rightarrow \quad A = -E ] exercice corrige electrocinetique
[ V_C(t) = B e^-(t - t_1)/\tau ]
With ( i(t) = C \fracdV_Cdt ), we get:
[ \boxed\tau = 100 \ \textms ] At ( t_1 = 0.5 \ \texts ): [ E = V_R(t) + V_C(t) = R
[ V_C(t) = E + A e^-t/RC ]